7v^2+6v-6=7v

Solution for 7v^2+6v-6=7v equation:

7v^2+6v-6=7v

We move all terms to the left:

7v^2+6v-6-(7v)=0

We add all the numbers together, and all the variables

7v^2-1v-6=0

a = 7; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·7·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*7}=\frac{-12}{14}
=-6/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*7}=\frac{14}{14}
=1
$